JEE Main 202229 Jun, Morning shiftMathematicsMediumIntegral Calculus369× since 2002The area enclosed by y² = 8x and y = 2\sqrt22 x that lies outside the triangle formed by y = 2\sqrt22 x, x = 1, y = 22\sqrt22, is equal to:AOption A. 1626{{16\sqrt 2 } \over 6}6162BOption B. 1126{{11\sqrt 2 } \over 6}6112COption C. 1326{{13\sqrt 2 } \over 6}6132DOption D. 526{{5\sqrt 2 } \over 6}652CheckSkip · show solution
