JEE Main 20211 Sep, Evening shiftMathematicsMediumIntegral Calculus369× since 2002The area, enclosed by the curves y=sinx+cosxy = \sin x + \cos xy=sinx+cosx and y=∣cosx−sinx∣y = \left| {\cos x - \sin x} \right|y=∣cosx−sinx∣ and the lines x=0,x=π2x = 0,x = {\pi \over 2}x=0,x=2π, is :AOption A. 22(2−1)2\sqrt 2 (\sqrt 2 - 1)22(2−1)BOption B. 2(2+1)2(\sqrt 2 + 1)2(2+1)COption C. 4(2−1)4(\sqrt 2 - 1)4(2−1)DOption D. 22(2+1)2\sqrt 2 (\sqrt 2 + 1)22(2+1)CheckSkip · show solution
