The area enclosed between the curve y = log e (x + e) and the coordinate axes is:

Integral Calculus: JEE Main 2005 Mathematics question

JEE Main 2005 · Annual, Paper 1 · Q2877

JEE Main 2005Annual, Paper 1MathematicsMediumIntegral Calculus369× since 2002

The area enclosed between the curve

y = {\log _e}\left( {x + e} \right)

and the coordinate axes is :

JEE Main 2005 · Annual, Paper 1 · Q2877

JEE Main 2005Annual, Paper 1MathematicsMediumIntegral Calculus369× since 2002

The area enclosed between the curve

y = {\log _e}\left( {x + e} \right)

and the coordinate axes is :