JEE Main 202226 Jul, Evening shiftMathematicsMediumIntegral Calculus369× since 2002The area bounded by the curves y=∣x2−1∣y=\left|x^{2}-1\right|y=x2−1 and y=1y=1y=1 isAOption A. 23(2+1)\frac{2}{3}(\sqrt{2}+1)32(2+1)BOption B. 43(2−1)\frac{4}{3}(\sqrt{2}-1)34(2−1)COption C. 2(2−1)2(\sqrt{2}-1)2(2−1)DOption D. 83(2−1)\frac{8}{3}(\sqrt{2}-1)38(2−1)CheckSkip · show solution
