JEE Main 202226 Jun, Morning shiftMathematicsMediumIntegral Calculus369× since 2002The area bounded by the curve y = |x² −-− 9| and the line y = 3 is :AOption A. 4(23+6−4)4(2\sqrt 3 + \sqrt 6 - 4)4(23+6−4)BOption B. 4(43+6−4)4(4\sqrt 3 + \sqrt 6 - 4)4(43+6−4)COption C. 8(43+36−9)8(4\sqrt 3 + 3\sqrt 6 - 9)8(43+36−9)DOption D. 8(43+6−9)8(4\sqrt 3 + \sqrt 6 - 9)8(43+6−9)CheckSkip · show solution
