JEE Main 20238 Apr, Evening shiftPhysicsHardGravitation159× since 2002The acceleration due to gravity at height hhh above the earth if h<<Rh << \mathrm{R}h<<R (Radius of earth) is given byAOption A. g′=g(1−2hR)g^{\prime}=g\left(1-\frac{2 h}{R}\right)g′=g(1−R2h)BOption B. g′=g(1−2h2R2)g^{\prime}=g\left(1-\frac{2 h^{2}}{R^{2}}\right)g′=g(1−R22h2)COption C. g′=g(1−h22R2)g^{\prime}=g\left(1-\frac{h^{2}}{2 R^{2}}\right)g′=g(1−2R2h2)DOption D. g′=g(1−h2R)g^{\prime}=g\left(1-\frac{h}{2 R}\right)g′=g(1−2Rh)CheckSkip · show solution
