The absolute difference of the coefficients of x¹⁰ and x⁷ in the expansion of (2 x²+1/(2 x))¹¹ is equal to:

Binomial Theorem and Its Simple Applications: JEE Main 2023 Mathematics question

JEE Main 2023 · 8 Apr, Evening shift · Q2945

JEE Main 20238 Apr, Evening shiftMathematicsMediumBinomial Theorem and Its Simple Applications131× since 2002

The absolute difference of the coefficients of

x^{10}

and

x^{7}

in the expansion of

\left(2 x^{2}+\frac{1}{2 x}\right)^{11}

is equal to :

JEE Main 2023 · 8 Apr, Evening shift · Q2945

JEE Main 20238 Apr, Evening shiftMathematicsMediumBinomial Theorem and Its Simple Applications131× since 2002

The absolute difference of the coefficients of

x^{10}

and

x^{7}

in the expansion of

\left(2 x^{2}+\frac{1}{2 x}\right)^{11}

is equal to :