JEE Main 202228 Jul, Evening shiftMathematicsEasyComplex Numbers and Quadratic Equations264× since 2002 Let S={x∈[−6,3]−{−2,2}:∣x+3∣−1∣x∣−2≥0} and \text { Let } S=\left\{x \in[-6,3]-\{-2,2\}: \frac{|x+3|-1}{|x|-2} \geq 0\right\} \text { and } Let S={x∈[−6,3]−{−2,2}:∣x∣−2∣x+3∣−1≥0} and T={x∈Z:x2−7∣x∣+9≤0}. T=\left\{x \in \mathbb{Z}: x^{2}-7|x|+9 \leq 0\right\} \text {. }T={x∈Z:x2−7∣x∣+9≤0}. Then the number of elements in S∩T\mathrm{S} \cap \mathrm{T}S∩T is :AOption A. 7BOption B. 5COption C. 4DOption D. 3CheckSkip · show solution
