JEE Main 20244 Apr, Morning shiftMathematicsMediumIntegral Calculus369× since 2002
\text { Let } f(x)=\left\{\begin{array}{lr}
-2, & -2 \leq x \leq 0 \\
x-2, & 0< x \leq 2
\end{array} \text { and } \mathrm{h}(x)=f(|x|)+|f(x)| \text {. Then } \int_\limits{-2}^2 \mathrm{~h}(x) \mathrm{d} x\right. \text { is equal to: }