JEE Main 202228 Jul, Evening shiftMathematicsMediumSets, Relations and Functions168× since 2002 Let f(x)=ax2+bx+c be such that f(1)=3,f(−2)=λ and \text { Let } f(x)=a x^{2}+b x+c \text { be such that } f(1)=3, f(-2)=\lambda \text { and } Let f(x)=ax2+bx+c be such that f(1)=3,f(−2)=λ and f(3)=4f(3)=4f(3)=4. If f(0)+f(1)+f(−2)+f(3)=14f(0)+f(1)+f(-2)+f(3)=14f(0)+f(1)+f(−2)+f(3)=14, then λ\lambdaλ is equal to :AOption A. −-−4BOption B. 132\frac{13}{2}213COption C. 232\frac{23}{2}223DOption D. 4CheckSkip · show solution
