JEE Main 20246 Apr, Morning shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002 If f(x)={x3sin(1x),x≠00,x=0, then \text { If } f(x)=\left\{\begin{array}{ll} x^3 \sin \left(\frac{1}{x}\right), & x \neq 0 \\ 0 & , x=0 \end{array}\right. \text {, then } If f(x)={x3sin(x1),0x=0,x=0, then AOption A. f′′(0)=0f^{\prime \prime}(0)=0f′′(0)=0BOption B. f′′(0)=1f^{\prime \prime}(0)=1f′′(0)=1COption C. f′′(2π)=24−π22πf^{\prime \prime}\left(\frac{2}{\pi}\right)=\frac{24-\pi^2}{2 \pi}f′′(π2)=2π24−π2DOption D. f′′(2π)=12−π22πf^{\prime \prime}\left(\frac{2}{\pi}\right)=\frac{12-\pi^2}{2 \pi}f′′(π2)=2π12−π2CheckSkip · show solution
