JEE Main 202226 Jul, Evening shiftMathematicsEasyBinomial Theorem and Its Simple Applications131× since 2002∑i,j=0i≠jnnCi nCj\sum\limits_{\matrix{ {i,j = 0} \cr {i \ne j} \cr } }^n {{}^n{C_i}\,{}^n{C_j}}i,j=0i=j∑nnCinCj is equal toAOption A. 22n−2nCn2^{2 n}-{ }^{2 n} C_{n}22n−2nCnBOption B. 22n−1−2n−1Cn−1{2^{2n - 1}} - {}^{2n - 1}{C_{n - 1}}22n−1−2n−1Cn−1COption C. 22n−122nCn2^{2 n}-\frac{1}{2}{ }^{2 n} C_{n}22n−212nCnDOption D. 22n−1+2n−1Cn{2^{2n - 1}} + {}^{2n - 1}{C_n}22n−1+2n−1CnCheckSkip · show solution
