JEE Main 202127 Aug, Morning shiftMathematicsEasyBinomial Theorem and Its Simple Applications131× since 2002∑k=020(20Ck)2\sum\limits_{k = 0}^{20} {{{\left( {{}^{20}{C_k}} \right)}^2}}k=0∑20(20Ck)2 is equal to :AOption A. 40C21{}^{40}{C_{21}}40C21BOption B. 40C19{}^{40}{C_{19}}40C19COption C. 40C20{}^{40}{C_{20}}40C20DOption D. 41C20{}^{41}{C_{20}}41C20CheckSkip · show solution
