Sulphurous acid (H₂SO₃) has Ka₁ = 1.7 × 10⁻² and Ka₂ = 6.4 × 10⁻⁸. The pH of 0.588 M H₂SO₃ is _ _ _ _ _. (Round off to the Nearest Integer).

Equilibrium: JEE Main 2021 Chemistry question

JEE Main 2021 · 16 Mar, Evening shift · Q11

JEE Main 202116 Mar, Evening shiftChemistryMediumEquilibrium123× since 2002

Sulphurous acid (H₂SO₃) has Ka₁ = 1.7

\times

10^

-

2 and Ka₂ = 6.4

\times

10^

-

8. The pH of 0.588 M H₂SO₃ is __________. (Round off to the Nearest Integer).

Your answerType your answer. Integers and decimals are accepted.