Sucrose hydrolyses in acid solution into glucose and fructose following first order rate law with a half-life of 3.33 h at 25° C. After 9 h, the fraction of sucrose remaining is f. The value of log ₁₀(1/f) is _ _ _ _ × 10⁻². (Rounded off to the nearest integer) [Assume: ln 10 = 2.303, ln 2 = 0.693]

Chemical Kinetics: JEE Main 2021 Chemistry question

JEE Main 2021 · 24 Feb, Evening shift · Q4

JEE Main 202124 Feb, Evening shiftChemistryMediumChemical Kinetics62× since 2002

Sucrose hydrolyses in acid solution into glucose and fructose following first order rate law with a half-life of 3.33 h at 25

^\circ

C. After 9 h, the fraction of sucrose remaining is f. The value of

{\log _{10}}\left( {{1 \over f}} \right)

is ________

\times

10^

-

2. (Rounded off to the nearest integer) [Assume : ln 10 = 2.303, ln 2 = 0.693]

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2021 Chemical Kinetics Question with Answer (24 Feb Evening shift, Q4) | JEE Arc