JEE Main 2009Annual, Paper 1MathematicsMediumMathematical Reasoning115× since 2008Statement-1 : ∼(p↔∼q)\sim \left( {p \leftrightarrow \sim q} \right)∼(p↔∼q) is equivalent to p↔q{p \leftrightarrow q}p↔q. Statement-2 : ∼(p↔∼q)\sim \left( {p \leftrightarrow \sim q} \right)∼(p↔∼q) is a tautology.AOption A. Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1BOption B. Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1COption C. Statement-1 is true, Statement-2 is falseDOption D. Statement-1 is false, Statement-2 is trueCheckSkip · show solution
