JEE Main 20178 Apr, Morning shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002limx→3\mathop {\lim }\limits_{x \to 3}x→3lim 3x−32x−4−2{{\sqrt {3x} - 3} \over {\sqrt {2x - 4} - \sqrt 2 }}2x−4−23x−3 is equal to :AOption A. 3\sqrt 33BOption B. 12{1 \over {\sqrt 2 }}21COption C. 32{{\sqrt 3 } \over 2}23DOption D. 122{1 \over {2\sqrt 2 }}221CheckSkip · show solution
