JEE Main 2010Annual, Paper 1MathematicsMediumDifferential Equations163× since 2002Solution of the differential equation cosx dy=y(sinx−y)dx, 0<x<π2\cos x\,dy = y\left( {\sin x - y} \right)dx,\,\,0 < x <{\pi \over 2}cosxdy=y(sinx−y)dx,0<x<2π is :AOption A. ysecx=tanx+cy\sec x = \tan x + cysecx=tanx+cBOption B. ytanx=secx+cy\tan x = \sec x + cytanx=secx+cCOption C. tanx=(secx+c)y\tan x = \left( {\sec x + c} \right)ytanx=(secx+c)yDOption D. secx=(tanx+c)y\sec x = \left( {\tan x + c} \right)ysecx=(tanx+c)yCheckSkip · show solution
