JEE Main 2002Annual, Paper 1MathematicsEasyIntegral Calculus369× since 2002∫02[x2]dx\int\limits_0^2 {\left[ {{x^2}} \right]dx}0∫2[x2]dx isAOption A. 2−22 - \sqrt 22−2BOption B. 2+22 + \sqrt 22+2COption C. 2−1\,\sqrt 2 - 12−1DOption D. −2−3+5- \sqrt 2 - \sqrt 3 + 5−2−3+5CheckSkip · show solution
