If the square of the shortest distance between the lines (x-2)/1=(y-1)/2=(z+3)/3 and (x+1)/2=(y+3)/4=(z+5)/5 is m/n, where m, n are coprime numbers, then m+n is equal to:

Three Dimensional Geometry: JEE Main 2025 Mathematics question

JEE Main 2025 · January, Unspecified (session-level dataset) · Q231

JEE Main 2025January, Unspecified (session-level dataset)MathematicsMediumThree Dimensional Geometry249× since 2002

If the square of the shortest distance between the lines

\frac{x-2}{1}=\frac{y-1}{2}=\frac{z+3}{3}

and

\frac{x+1}{2}=\frac{y+3}{4}=\frac{z+5}{5}

\frac{m}{n}

, where

m, n

are coprime numbers, then

m+n

is equal to:

JEE Main 2025 Three Dimensional Geometry Question with Solution (January Unspecified (session-level dataset), Q231) | JEE Arc