JEE Main 2025January, Unspecified (session-level dataset)MathematicsMediumThree Dimensional Geometry249× since 2002The distance of the line x−22=y−63=z−34\frac{x-2}{2}=\frac{y-6}{3}=\frac{z-3}{4}2x−2=3y−6=4z−3 from the point (1,4,0)(1,4,0)(1,4,0) along the line x4=y−22=z+33\frac{x}{4}=\frac{y-2}{2}=\frac{z+3}{3}4x=2y−2=3z+3 is:AOption A. 17\sqrt{17}17BOption B. 15\sqrt{15}15COption C. 14\sqrt{14}14DOption D. 13\sqrt{13}13CheckStep-by-step hintSkip · show solution
