Unclassified (maths): JEE Main 2025 Mathematics question

Let $L_1: \frac{x-1}{3} = \frac{y-1}{4} = \frac{z+1}{0}$ and $L_2: \frac{x-2}{2} = \frac{y}{0} = \frac{z+4}{0}$, $\alpha \in \mathbb{R}$, be two lines, which intersect at the point $B$. If $P$ is the foot of perpendicular from the point $A(1, 1, -1)$ on $L_2$, then the value of $26 \alpha (PB)^2$ is: