JEE Main 2025January, Unspecified (session-level dataset)MathematicsMediumIntegral Calculus369× since 2002The area of the region, inside the circle (x−23)2+y2=12(x - 2\sqrt{3})^2 + y^2 = 12(x−23)2+y2=12 and outside the parabola y2=23xy^2 = 2\sqrt{3} xy2=23x is:AOption A. 3π+83\pi + 83π+8BOption B. 6π−166\pi - 166π−16COption C. 3π−83\pi - 83π−8DOption D. 6π−86\pi - 86π−8CheckSkip · show solution
