JEE Main 2025January, Unspecified (session-level dataset)MathematicsMediumUnclassified (maths)Let y=y(x)y = y(x)y=y(x) be the solution of the differential equation 2cosxdydx=sin2x−4ysinx2 \cos x \frac{dy}{dx} = \sin 2x - 4y \sin x2cosxdxdy=sin2x−4ysinx, x∈(0,π2)x \in \left(0, \frac{\pi}{2}\right)x∈(0,2π). If y(π3)=0y\left(\frac{\pi}{3}\right) = 0y(3π)=0, then y′(π4)+y(π4)y'\left(\frac{\pi}{4}\right) + y\left(\frac{\pi}{4}\right)y′(4π)+y(4π) is equal to:Your answerInteger or decimalCheckStep-by-step hintSkip · show solution