JEE Main 2025January, Unspecified (session-level dataset)MathematicsMediumCoordinate Geometry478× since 2002The equation of the chord of the ellipse x225+y216=1\frac{x^2}{25} + \frac{y^2}{16} = 125x2+16y2=1, whose mid-point is (3,1)(3, 1)(3,1), is:AOption A. 48x+25y=16948x + 25y = 16948x+25y=169BOption B. 5x+16y=315x + 16y = 315x+16y=31COption C. 25x+101y=17625x + 101y = 17625x+101y=176DOption D. 4x+122y=1344x + 122y = 1344x+122y=134CheckSkip · show solution