JEE Main 2025January, Unspecified (session-level dataset)MathematicsMediumSequence and Series179× since 2002Let ⟨an⟩\langle a_n \rangle⟨an⟩ be a sequence such that a0=0a_0 = 0a0=0, a1=12a_1 = \frac{1}{2}a1=21 and 2an+2=5an+1−3an2 a_{n+2} = 5 a_{n+1} - 3 a_n2an+2=5an+1−3an, n=0,1,2,3,…n = 0, 1, 2, 3, \ldotsn=0,1,2,3,…. Then ∑k=1100ak\sum_{k=1}^{100} a_k∑k=1100ak is equal toAOption A. 3a99−1003 a_{99} - 1003a99−100BOption B. 3a100−1003 a_{100} - 1003a100−100COption C. 3a99+1003 a_{99} + 1003a99+100DOption D. 3a100+1003 a_{100} + 1003a100+100CheckSkip · show solution