JEE Main 2025January, Unspecified (session-level dataset)MathematicsMediumSequence and Series179× since 2002Let TrT_rTr be the rthr^{\text{th}}rth term of an A.P. If for some mmm, Tm=125T_m = \frac{1}{25}Tm=251, T25=120T_{25} = \frac{1}{20}T25=201, and 20∑r=125Tr=1320 \sum_{r=1}^{25} T_r = 1320∑r=125Tr=13, then 5m∑r=m2mTr5m \sum_{r=m}^{2m} T_r5m∑r=m2mTr is equal toAOption A. 98BOption B. 126COption C. 142DOption D. 112CheckSkip · show solution