JEE Main 2025January, Unspecified (session-level dataset)MathematicsMediumUnclassified (maths)Let f(x)=limn→∞∑t=0n(tan(x2n+1)+tan3(x2n+1)1−tan3(x2n+1))f(x) = \lim_{n \to \infty} \sum_{t=0}^{n} \left(\frac{\tan \left(\frac{x}{2^{n+1}}\right) + \tan^3 \left(\frac{x}{2^{n+1}}\right)}{1 - \tan^3 \left(\frac{x}{2^{n+1}}\right)}\right)f(x)=limn→∞∑t=0n(1−tan3(2n+1x)tan(2n+1x)+tan3(2n+1x)). Then limx→0x(x−f(x))\lim_{x \to 0} \frac{x}{(x - f(x))}limx→0(x−f(x))x is equal to:Your answerInteger or decimalCheckStep-by-step hintSkip · show solution
