JEE Main 2025January, Unspecified (session-level dataset)MathematicsMediumUnclassified (maths)If y=y(x)y = y(x)y=y(x) is the solution of the differential equation 4−x2dydx=((sin−1(x2))2−y)sin−1(x2)\sqrt{4 - x^2} \frac{dy}{dx} = \left(\left(\sin^{-1}\left(\frac{x}{2}\right)\right)^2 - y\right) \sin^{-1}\left(\frac{x}{2}\right)4−x2dxdy=((sin−1(2x))2−y)sin−1(2x), −2≤x≤2-2 \leq x \leq 2−2≤x≤2, y(2)=π2−84y(2) = \frac{\pi^2 - 8}{4}y(2)=4π2−8, then y2(0)y^2(0)y2(0) is equal to:Your answerInteger or decimalCheckStep-by-step hintSkip · show solution
