JEE Main 2025January, Unspecified (session-level dataset)MathematicsMediumSets, Relations and Functions168× since 2002Let f(x)=2x+2+1622x+1+2x+4+32f(x) = \frac{2^{x+2} + 16}{2^{2x+1} + 2^{x+4} + 32}f(x)=22x+1+2x+4+322x+2+16. Then the value of 8(f(115)+f(215)+…+f(5915))8\left(f\left(\frac{1}{15}\right) + f\left(\frac{2}{15}\right) + \ldots + f\left(\frac{59}{15}\right)\right)8(f(151)+f(152)+…+f(1559)) is equal toAOption A. 92BOption B. 118COption C. 102DOption D. 108CheckSkip · show solution