JEE Main 2025January, Unspecified (session-level dataset)MathematicsMediumIntegral Calculus369× since 2002The area of the region enclosed by the curves y=x2−4x+4y=x^2-4x+4y=x2−4x+4 and y2=16−8xy^2=16-8xy2=16−8x is:AOption A. 83\frac{8}{3}38BOption B. 43\frac{4}{3}34COption C. 8DOption D. 5CheckSkip · show solution
