Let a random variable X take values 0, 1, 2 and 3 with P(X = 0) = P(X = 1) = p and P(X = 2) = P(X = 3) = (1 - 2p)/2. If E(X²) = 2E(X), then the value of 8p - 1 is:

Statistics and Probability: JEE Main 2025 Mathematics question

JEE Main 2025 · April, Unspecified (session-level dataset) · Q156

JEE Main 2025April, Unspecified (session-level dataset)MathematicsMediumStatistics and Probability258× since 2002

Let a random variable X take values 0, 1, 2 and 3 with P(X = 0) = P(X = 1) = p and P(X = 2) = P(X = 3) =

\tfrac{1 - 2p}{2}

. If

E(X^2) = 2E(X)

, then the value of

8p - 1

is:

JEE Main 2025 · April, Unspecified (session-level dataset) · Q156

JEE Main 2025April, Unspecified (session-level dataset)MathematicsMediumStatistics and Probability258× since 2002

Let a random variable X take values 0, 1, 2 and 3 with P(X = 0) = P(X = 1) = p and P(X = 2) = P(X = 3) =

\tfrac{1 - 2p}{2}

. If

E(X^2) = 2E(X)

, then the value of

8p - 1

is: