JEE Main 2025April, Unspecified (session-level dataset)MathematicsMediumUnclassified (maths)If ∫(1+x2+x)10(1+x2−x)9 dx=1m((1+x2+x)n(1+x2−x))+C\displaystyle\int \frac{(\sqrt{1+x^2}+x)^{10}}{(\sqrt{1+x^2}-x)^{9}}\,dx = \frac{1}{m}\bigl((\sqrt{1+x^2}+x)^{n}(\sqrt{1+x^2}-x)\bigr)+C∫(1+x2−x)9(1+x2+x)10dx=m1((1+x2+x)n(1+x2−x))+C, where CCC is the constant of integration and m,n∈Nm,n\in\mathbb{N}m,n∈N, then m+nm+nm+n is equal to:Your answerInteger or decimalCheckStep-by-step hintSkip · show solution
