If the sum of the first 20 terms of the series (4·1)/(4+3·1²+1⁴)+(4·2)/(4+3·2²+2⁴)+(4·3)/(4+3·3²+3⁴)+ is m/n, where m and n are coprime, then m+n is equal to:

Sequence and Series: JEE Main 2025 Mathematics question

JEE Main 2025 · April, Unspecified (session-level dataset) · Q112

JEE Main 2025April, Unspecified (session-level dataset)MathematicsMediumSequence and Series179× since 2002

If the sum of the first 20 terms of the series

\displaystyle\frac{4\cdot1}{4+3\cdot1^2+1^4}+\frac{4\cdot2}{4+3\cdot2^2+2^4}+\frac{4\cdot3}{4+3\cdot3^2+3^4}+\dots

\tfrac{m}{n}

, where

m

and

n

are coprime, then

m+n

is equal to: