Let (1+x+x²)¹⁰ = a₀ + a₁ x + a₂ x² + + a₂₀ x²⁰. If (a₁ + a₃ + a₅ + + a₁₉) - 11a₂ = 121k, then k is equal to:

Unclassified (maths): JEE Main 2025 Mathematics question

JEE Main 2025 · April, Unspecified (session-level dataset) · Q72

JEE Main 2025April, Unspecified (session-level dataset)MathematicsMediumUnclassified (maths)

Let

(1+x+x^2)^{10} = a_0 + a_1 x + a_2 x^2 + \dots + a_{20} x^{20}

. If

(a_1 + a_3 + a_5 + \dots + a_{19}) - 11a_2 = 121k

, then

k

is equal to:

Your answerInteger or decimal