JEE Main 2025April, Unspecified (session-level dataset)MathematicsMediumLimit, Continuity and Differentiability420× since 2002For α,β,γ∈R\alpha,\beta,\gamma\in\mathbb{R}α,β,γ∈R, if limx→0x2sin(αx)+(γ−1)ex2sin(2x)−βx=3\displaystyle\lim_{x\to0}\frac{x^2\sin(\alpha x)+(\gamma-1)e^{x^2}}{\sin(2x)-\beta x}=3x→0limsin(2x)−βxx2sin(αx)+(γ−1)ex2=3, then β+γ−α\beta+\gamma-\alphaβ+γ−α is equal to:AOption A. 7BOption B. 4COption C. 6DOption D. -1CheckSkip · show solution
