JEE Main 201910 Jan, Evening shiftMathematicsEasyThree Dimensional Geometry249× since 2002On which of the following lines lies the point of intersection of the line, x−42=y−52=z−31{{x - 4} \over 2} = {{y - 5} \over 2} = {{z - 3} \over 1}2x−4=2y−5=1z−3 and the plane, x + y + z = 2 ?AOption A. x−41=y−51=z−5−1{{x - 4} \over 1} = {{y - 5} \over 1} = {{z - 5} \over { - 1}}1x−4=1y−5=−1z−5BOption B. x−22=y−32=z+33{{x - 2} \over 2} = {{y - 3} \over 2} = {{z + 3} \over 3}2x−2=2y−3=3z+3COption C. x−11=y−32=z+4−5{{x - 1} \over 1} = {{y - 3} \over 2} = {{z + 4} \over { - 5}}1x−1=2y−3=−5z+4DOption D. x+33=4−y3=z+1−2{{x + 3} \over 3} = {{4 - y} \over 3} = {{z + 1} \over { - 2}}3x+3=34−y=−2z+1CheckSkip · show solution
