On the x-axis and at a distance x from the origin, the gravitational field due a mass distribution is given by Ax/((x² + a²)^(3/2)) in the x-direction. The magnitude of gravitational potential on the x-axis at a distance x, taking its value to be zero at infinity, is:

Gravitation: JEE Main 2020 Physics question

JEE Main 2020 · 4 Sep, Morning shift · Q7138

JEE Main 20204 Sep, Morning shiftPhysicsMediumGravitation159× since 2002

On the x-axis and at a distance x from the origin, the gravitational field due a mass distribution is given by

{{Ax} \over {{{\left( {{x^2} + {a^2}} \right)}^{3/2}}}}

in the x-direction. The magnitude of gravitational potential on the x-axis at a distance x, taking its value to be zero at infinity, is:

JEE Main 2020 Gravitation Question with Solution (4 Sep Morning shift, Q7138) | JEE Arc

JEE Main 2020 · 4 Sep, Morning shift · Q7138

JEE Main 20204 Sep, Morning shiftPhysicsMediumGravitation159× since 2002

On the x-axis and at a distance x from the origin, the gravitational field due a mass distribution is given by

{{Ax} \over {{{\left( {{x^2} + {a^2}} \right)}^{3/2}}}}

in the x-direction. The magnitude of gravitational potential on the x-axis at a distance x, taking its value to be zero at infinity, is: