JEE Main 202313 Apr, Morning shiftMathematicsHardLimit, Continuity and Differentiability420× since 2002\max _\limits{0 \leq x \leq \pi}\left\{x-2 \sin x \cos x+\frac{1}{3} \sin 3 x\right\}=AOption A. 5π+2+336\frac{5 \pi+2+3 \sqrt{3}}{6}65π+2+33BOption B. 0COption C. π+2−336\frac{\pi+2-3 \sqrt{3}}{6}6π+2−33DOption D. π\piπCheckSkip · show solution
