lim x → (π)/2 ([ 1 - tan (x/2) ][ 1 - sin x ])/([ 1 + tan (x/2) ][ π - 2x ]³) is

Limit, Continuity and Differentiability: JEE Main 2003 Mathematics question

JEE Main 2003 · Annual, Paper 1 · Q4264

JEE Main 2003Annual, Paper 1MathematicsMediumLimit, Continuity and Differentiability420× since 2002

\mathop {\lim }\limits_{x \to {\pi \over 2}} {{\left[ {1 - \tan \left( {{x \over 2}} \right)} \right]\left[ {1 - \sin x} \right]} \over {\left[ {1 + \tan \left( {{x \over 2}} \right)} \right]{{\left[ {\pi - 2x} \right]}^3}}}

JEE Main 2003 · Annual, Paper 1 · Q4264

JEE Main 2003Annual, Paper 1MathematicsMediumLimit, Continuity and Differentiability420× since 2002

\mathop {\lim }\limits_{x \to {\pi \over 2}} {{\left[ {1 - \tan \left( {{x \over 2}} \right)} \right]\left[ {1 - \sin x} \right]} \over {\left[ {1 + \tan \left( {{x \over 2}} \right)} \right]{{\left[ {\pi - 2x} \right]}^3}}}