JEE Main 20203 Sep, Evening shiftMathematicsHardLimit, Continuity and Differentiability420× since 2002limx→a(a+2x)13−(3x)13(3a+x)13−(4x)13\mathop {\lim }\limits_{x \to a} {{{{\left( {a + 2x} \right)}^{{1 \over 3}}} - {{\left( {3x} \right)}^{{1 \over 3}}}} \over {{{\left( {3a + x} \right)}^{{1 \over 3}}} - {{\left( {4x} \right)}^{{1 \over 3}}}}}x→alim(3a+x)31−(4x)31(a+2x)31−(3x)31 (aaa ≠\ne= 0) is equal to :AOption A. (29)(23)13\left( {{2 \over 9}} \right){\left( {{2 \over 3}} \right)^{{1 \over 3}}}(92)(32)31BOption B. (23)(29)13\left( {{2 \over 3}} \right){\left( {{2 \over 9}} \right)^{{1 \over 3}}}(32)(92)31COption C. (23)43{\left( {{2 \over 3}} \right)^{{4 \over 3}}}(32)34DOption D. (29)43{\left( {{2 \over 9}} \right)^{{4 \over 3}}}(92)34CheckSkip · show solution
