JEE Main 20206 Sep, Morning shiftMathematicsMediumIntegral Calculus369× since 2002

$\mathop {\lim }\limits_{x \to 1} \left( {{{\int\limits_0^{{{\left( {x - 1} \right)}^2}} {t\cos \left( {{t^2}} \right)dt} } \over {\left( {x - 1} \right)\sin \left( {x - 1} \right)}}} \right)$

• AOption A. is equal to 0
• BOption B. is equal to ${1 \over 2}$
• COption C. does not exist
• DOption D. is equal to $- {1 \over 2}$

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