JEE Main 201911 Jan, Evening shiftMathematicsEasyLimit, Continuity and Differentiability420× since 2002limx→0xcot(4x)sin2xcot2(2x)\mathop {\lim }\limits_{x \to 0} {{x\cot \left( {4x} \right)} \over {{{\sin }^2}x{{\cot }^2}\left( {2x} \right)}}x→0limsin2xcot2(2x)xcot(4x) is equal to :AOption A. 0BOption B. 4COption C. 1DOption D. 2CheckSkip · show solution