JEE Main 2002Annual, Paper 1MathematicsEasyLimit, Continuity and Differentiability420× since 2002limx→01−cos2x2x\mathop {\lim }\limits_{x \to 0} {{\sqrt {1 - \cos 2x} } \over {\sqrt 2 x}}x→0lim2x1−cos2x isAOption A. 111BOption B. −1-1−1COption C. zeroDOption D. does not existCheckSkip · show solution