JEE Main 20208 Jan, Morning shiftMathematicsEasyLimit, Continuity and Differentiability420× since 2002limx→0(3x2+27x2+2)1x2\mathop {\lim }\limits_{x \to 0} {\left( {{{3{x^2} + 2} \over {7{x^2} + 2}}} \right)^{{1 \over {{x^2}}}}}x→0lim(7x2+23x2+2)x21 is equal toAOption A. eBOption B. e²COption C. 1e2{1 \over {{e^2}}}e21DOption D. 1e{1 \over e}e1CheckSkip · show solution
