JEE Main 202124 Feb, Morning shiftMathematicsEasyIntegral Calculus369× since 2002limx→0∫0x2(sint)dtx3\mathop {\lim }\limits_{x \to 0} {{\int\limits_0^{{x^2}} {\left( {\sin \sqrt t } \right)dt} } \over {{x^3}}}x→0limx30∫x2(sint)dt is equal to :AOption A. 115{1 \over {15}}151BOption B. 0COption C. 23{2 \over 3}32DOption D. 32{3 \over 2}23CheckSkip · show solution