JEE Main 201910 Apr, Morning shiftMathematicsMediumIntegral Calculus369× since 2002limn→∞((n+1)1/3n4/3+(n+2)1/3n4/3+.......+(2n)1/3n4/3)\mathop {\lim }\limits_{n \to \infty } \left( {{{{{(n + 1)}^{1/3}}} \over {{n^{4/3}}}} + {{{{(n + 2)}^{1/3}}} \over {{n^{4/3}}}} + ....... + {{{{(2n)}^{1/3}}} \over {{n^{4/3}}}}} \right)n→∞lim(n4/3(n+1)1/3+n4/3(n+2)1/3+.......+n4/3(2n)1/3) is equal to :AOption A. 43(2)3/4{4 \over 3}{\left( 2 \right)^{3/4}}34(2)3/4BOption B. 34(2)4/3−34{3 \over 4}{\left( 2 \right)^{4/3}} - {3 \over 4}43(2)4/3−43COption C. 43(2)4/3{4 \over 3}{\left( 2 \right)^{4/3}}34(2)4/3DOption D. 34(2)4/3−43{3 \over 4}{\left( 2 \right)^{4/3}} - {4 \over 3}43(2)4/3−34CheckSkip · show solution
