JEE Main 2015Session, Shift 1MathematicsMediumCoordinate Geometry478× since 2002Locus of the image of the point (2,3)(2, 3)(2,3) in the line (2x−3y+4)+k(x−2y+3)=0, k∈R,\left( {2x - 3y + 4} \right) + k\left( {x - 2y + 3} \right) = 0,\,k \in R,(2x−3y+4)+k(x−2y+3)=0,k∈R, is a :AOption A. circle of radius 2\sqrt 22.BOption B. circle of radius 3\sqrt 33.COption C. straight line parallel to xxx-axisDOption D. straight line parallel to yyy-axisCheckSkip · show solution
