JEE Main 2002Annual, Paper 1MathematicsMediumCoordinate Geometry478× since 2002Locus of mid point of the portion between the axes of xxx coscoscos α+y sinα=p\alpha + y\,\sin \alpha = pα+ysinα=p where ppp is constant is :AOption A. x2+y2=4p2{x^2} + {y^2} = {4 \over {{p^2}}}x2+y2=p24BOption B. x2+y2=4p2{x^2} + {y^2} = 4{p^2}x2+y2=4p2COption C. 1x2+1y2=2p2{1 \over {{x^2}}} + {1 \over {{y^2}}} = {2 \over {{p^2}}}x21+y21=p22DOption D. 1x2+1y2=4p2{1 \over {{x^2}}} + {1 \over {{y^2}}} = {4 \over {{p^2}}}x21+y21=p24CheckSkip · show solution
