JEE Main 202225 Jul, Evening shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002limx→π482−(cosx+sinx)72−2sin2x\lim\limits_{x \rightarrow \frac{\pi}{4}} \frac{8 \sqrt{2}-(\cos x+\sin x)^{7}}{\sqrt{2}-\sqrt{2} \sin 2 x}x→4πlim2−2sin2x82−(cosx+sinx)7 is equal toAOption A. 14BOption B. 7COption C. 142\sqrt22DOption D. 72\sqrt22CheckSkip · show solution